Find the discriminant of the following quadratic equation and hence determine the nature of its roots: $x^{2}-2 \sqrt{2} x+1=0$

(D) Comparing the given equation $x^{2}-2 \sqrt{2} x+1=0$ with the standard form $ax^{2}+bx+c=0$,we get:
$a=1, b=-2 \sqrt{2}, c=1$
The discriminant $D$ is given by the formula $D=b^{2}-4ac$.
Substituting the values:
$D=(-2 \sqrt{2})^{2}-4(1)(1)$
$D=(4 \times 2)-4$
$D=8-4=4$
Since $D > 0$,the quadratic equation has two distinct real roots.